Hello Students,
Do you know ----
Q: Why are the atomic orbitals of oxygen atom in the molecular orbital diagram of carbon monoxide, CO, lower than those of carbon?
A: It is because the electronegativity of oxygen is larger than that of carbon.
Q: Which halogen has the largest oxidizing power?
A: Since the reduction potential of fluorine is the highest, its oxidizing power is the largest.
Q: Describe the numerical tendency of electronegativities of the elements in the periodic table.
A: They increase toward the right and decrease down the table. Namely, the electronegativity of alkali metal Cs is the smallest and that of fluorine F is the largest.
Comments
Post a Comment